Question

A particle with a charge of 2.5 c is taken from a point A of potential difference of 60 v and another point of B of potential difference 130 calculate work done

Answer 1

Answer:

Explanation:As it is given:

Charge on particle = 2.5 C

Potential on A = 60 v

Potential on B = 130 v

So we know that ,

Potential difference = work done/charge

So, p.d = 130-60 = 70

Now, putting value of p.d and charge in above formula.

We get,

70 = work/2.5

Work = 70 × 2.5 = 175 joule

Answer 2

Answer:

Work done is 175 j

Explanation:

here, q = 2.5

potential at point A is 60v and

potential at point B is 130v

now, potential difference between A and B is 130- 60 = 70v

we know, potential difference, v = work done, w / charge, q

                work done, w = v*q

                                    w = 70*2.5

                                    w = 175 j