Question

A particle with a mass of 1.00 *10-5sec a maximum speed of 1.00*103 m/s. calculate (a) the frequency and (b) the maximum displacement of the particle.

Answer 1

Explanation:

ANSWER

Given that T=1×10

−5

s so ω=

T

2π

=6.28×10

5

rad/s

The maximum speed should be V=Aω

so the max displacement or amplitude will be A=

ω

V

=

6.28×10

5

10

3

=0.159×10

−2

meter=1.59mm

Answer 2

Answer:

Given that T=1×10−5s so ω=T2π=6.28×105rad/s

The   maximum speed should be V=Aω 

so the max displacement or amplitude will be A=ωV=6.28×105103=0.159×10−2meter=1.59mm

Explanation:

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