A particle with a velocity of 2 m/s at = 0 moves along a straight line with a constant acceleration of 0.3 m/s². Find the distancement of the particle in 10s?
Answers
Velocity of the particle = u =2m/s (Given)
Time taken by the particle t = 10s (Given)
Constant acceleration = a = 0.2m/s² (Given)
Displacement refers to a vector quantity that refers as to how far out of place an object is. Displacement is the object's overall change in its position.
Using the second equation of motion -
S = ut + 1/2at²
= 2 × 10 + 0.5 × 0.2 × 10 × 10
= 20+10
= 30
Thus, if a particle with a velocity of 2m/s a t=0 moves along a straight line with a constant acceleration of 0.2m/s2, then the displacement of that particle in first 10 seconds is 30m.
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Answer:
Velocity of the particle = u =2m/s (Given)
Time taken by the particle t = 10s (Given)
El 52
Constant acceleration = a = 0.2m/s² (Given)
Displacement refers to a vector quantity that refers as to how far out of place an object is. Displacement is the object's overall change in its position.
Using the second equation of motion -
S = ut + 1/2at²
= 2 × 10 + 0.5 x 0.2 × 10 × 10
= 20+10
= 30
Thus, if a particle with a velocity of 2m/ s a t=0 moves along a straight line with a constant acceleration of 0.2m/s2, then the displacement of that particle in first 10 seconds is 30m.