A particle with initial velocity 60m/s is brought to rest is A distance of 120m.calculate retardation and time interval
Answers
Answered by
2
a =. -( 60*60 ÷2*120)=
=. -15
retardation =15m/s^2
t = 60/15
t = 4 second
=. -15
retardation =15m/s^2
t = 60/15
t = 4 second
Similar questions