Question

a particle with initial velocity v0 moves with constant acceleration in a straight line . Find the distance travelled in nth. second ​

Answer 1

At t= n sec, distance traveled by object is

s

n

=u(n)+

2

1

a(n)

2

In (n-1) sec, distance traveled by particle is

s

(n−1)

=u(n−1)+

2

1

a(n−1)

2

Therefore distance covered in n

th

sec, is

s

n

−s

(n−1)

=un+

2

1

an

2

−[u(n−1)+

2

1

a(n−1)

2

]

=un+

2

1

an

2

−[un−u+

2

1

a(n

2

−2n+1)]

=u+an−

2

1

a

∴s

nth

=u+

2

1

a[2n−1]