Question

A particle with mass m moving at speed v collides with a particle with mass 2m initially at rest. After the collision, the first particle comes to rest

Answer 1

we know that due to the law of conservation of momentum that,

m1u1 × m2u2 = m1v1×m2v2
wher m1 and m2 are masses respectively

u1 and u2 are initial velocities of the bodies respectivly

v1 and v2 are the final velocities of the masses respectively

substituting the values in the given equation

m(v) +2m (0) = m(0) +2m(x) (we are trying to find x)

mv=2mx


this shows that x=v/2
this means that the velocity of the second body after collosion is half of the first body's initial velocity


IF THIS HELPED PLEASE MARK BRAINLIEST