Question

a particle with rest mass m moves with speed 0.6 c its kinetic energy is

Answer 1

hence the answer is 1.62*1000000m J

Answer 2

Answer: $K.E = 2.025 m\times10^{16} J$

Explanation:

Given that,

Rest mass $m_{0} = m$

Speed $v = 0.6 c$

WE know that,

The mass is

$m' = \dfrac{m_{0}}{\sqrt{1-\dfrac{v^{2}}{c^{2}}}}$

Where, m' = mass of the particle

$m' = \dfrac{m}{0.8}$

The kinetic energy is

$K.E = \dfrac{1}{2}mv^{2}$

$K.E = \dfrac{1}{2}\times \dfrac{m}{0.8}\times 0.36 c^{2}$

$K.E = 0.22mc^{2} J$

$K.E = 2.025 m\times10^{16} J$

Hence, the kinetic energy is $K.E = 2.025 m\times10^{16} J$