Question

A particle with the charge of 1.5 coulomb is taken from a point A at a potential of 50v to another point b. at a point of 120v. calculate the work done

Answer 1

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C=1.5C
V1=50 V
V2=120 V
V=W/Q
Therefore,  W=VQ
W1= 1.5 X 50 = 75 J
W2 = 1.5 X 120 = 180 J
W = W2 - W1
     = 180 - 75
     =105 J