a particle with uniform acceleration in a straight line has a velocity vms¹ at a position x metre is given by v =√196-16x. it's acceleration is
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If the velocity of a particle is given by v= (180-16x) ^1/2 m/s then its acceleration will be V = √ (180 - 16x), v² = 180 - 16x,
Differentiate with dt ,
2vdv/dt = -16 dx/dt,
2va = -16v,
a = -8m/s².
form this your answer will be a = -8m/s².
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Answer:
-8m/s2 is the correct answer
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