Question

a particle with velocity of 2m/s at t =0 moves with a constant acceleration of 0.2m/s in 2the distance covered by the particle in 10s is​

Answer 1

Given :

a particle with velocity of 2 m/s at t =0 moves with a constant acceleration of 0.2 m/s²

To Find :

Distance covered by the particle in 10 s

Solution :

$\sf \bigstar\ \; \pink{s=ut+\dfrac{1}{2}at^2}$

where ,

• s denotes distance
• u denotes initial velocity
• t denotes time
• a denotes acceleration

______________________

Given ,

Initial velocity , u = 2 m/s

Acceleration , a = 0.2 m/s²

Time , t = 10 s

$\bigstar\ \; \sf \blue{s=ut+\dfrac{1}{2}at^2}\\\\\to \sf s=(2)(10)+\dfrac{1}{2}(0.2)(10)^2\\\\\to \sf s=20+10\\\\\leadsto \sf \green{s=30\ m}\ \; \bigstar$

Answer 2

Answer:

The distance covered by the particle in 10s is 30m.

Explanation:

Given that,

• Initial velocity (u) = 2m/s
• Acceleration (a) = 0.2 m/s²
• Time (t) = 10s

Applying 2nd equation of motion,

$\bigstar { \boxed{ \red{ \sf{s = ut + \frac{1}{2} at {}^{2} }}}}$

[ Putting values ]

$\longrightarrow \sf \: s = 2 \times 10 + \frac{1}{2} \times 0.2 \times (10) {}^{2} \\ \\ \longrightarrow \sf \: s = 20 + 0.1 \times 100 \\ \\ \longrightarrow \sf \: s = 20 + 10 \\ \\ \longrightarrow \sf \green{s = 30m} \: \bigstar$