Question

a particles has an initial velocity (3i + 5j) and an acceleration (5i + 2j) what is its speed after 5 sec​

Answer 1

Answer:

31.76m/s

Explanation:

use v=u+at

here initial velocity represented by u

v=(3i+5j)+5×(5i+2j)

v=(28i+15j)

now,we find magnitude of Velocity called speed

speed=√28²+15²=31.76m/s