a particles move 3m north, then 4m east and finally 6m south. calculate the total distance and the displacement of the particles
Answers
Answered by
3
Distance covered by the particle = 3+4+6 = 13 m
Displacement =
=
= 5
Displacement =
=
= 5
Answered by
2
Total distance: 3m+4m+6m=13m
Total displacement =shortest distance from initial positon to final position.
according to the question you can plot the diagram as here attached file.
Usign pythagoras theorem.
you can find the displacement as:3²+3²=(displacement)²
displacement=√9+9
=√18
Total displacement =shortest distance from initial positon to final position.
according to the question you can plot the diagram as here attached file.
Usign pythagoras theorem.
you can find the displacement as:3²+3²=(displacement)²
displacement=√9+9
=√18
Attachments:
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