Physics, asked by piyu6, 1 year ago

a particles move 3m north, then 4m east and finally 6m south. calculate the total distance and the displacement of the particles

Answers

Answered by MADHANSCTS
3
Distance covered by the particle = 3+4+6 = 13 m

Displacement =  \sqrt{3^{2}+4^{2}  }
                         =  \sqrt{25}
                         = 5
Answered by vishagh
2
Total distance: 3m+4m+6m=13m
Total displacement =shortest distance from initial positon to final position.
according to the question you can plot the diagram as here attached file.
Usign pythagoras theorem.
you can find the displacement as:3²+3²=(displacement)²
displacement=√9+9
                     =√18

Attachments:
Similar questions