Physics, asked by anaghjais14, 9 months ago

a particles moves on a circular path of radius R with uniform speed v, the magnitude of change in aceleration of particle in half revolution is​

Answers

Answered by VaishnaviMohan
2

Answer:

In uniform circular motion, angular velocity () is a vector quantity and is equal to the angular displacement (Δ, a vector quantity) divided by the change in time (Δ). Speed is equal to the arc length traveled (S) divided by the change in time (Δ), which is also equal to ||R.

Explanation:

May this ANSWER will help you plz mark has brainliest

Similar questions