A particles of mass 0.4 kg is attached to one end of a string of length 90cm. The particle moves in a horizontal circle with angular velocity of 2.5m/s with the string inclined at an angle of the vertical. Find The Angle. [g = 10 m/s2
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Answer:
m=150g=0.150kg,r=25cm=0.25m,h=90cm=0.90m
The tension in conical pendulum is
T=mg
(1+
h
2
r
2
)
=0.150∗9.8
(1+
0.90
2
0.25
2
)
=1.53N
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