Question

a particles of mass m carrying charge 'q1'is revolving around fixed charge '-q'in a circular path of radius r.calculate the period of revolution

Answer 1

Answer:

$T= 4\pi r \sqrt \dfrac {\pi E_o mr}{q_1 q_2}$

Explanation:

let -q fixed charge = $q_2$

radius = r {between two charges} (given)

electrostatic force = centripital force

$\dfrac{1} {4\pi E_o} \dfrac {q_1q_2}{{r}^{2}} = mr {\omega}^{2} = \dfrac {4 {\pi}^{2}mr}{{T}^{2}}$

${T}^{2} = \dfrac {(4 \pi E_o ) {r}^{2} (4 {\pi}^{2} mr)}{q_1q_2}$

$T= 4\pi r \sqrt \dfrac {\pi E_o mr}{q_1 q_2}$