Physics, asked by kikijojo, 6 months ago

A particles position is given by y= 2t^3 - 6t^2 + 4 as it moves along the y-axis.In the time interval between 1.0s and 3.0s , what is the average acceleration of the particle ?( in m/s^2)
PLEASE HELP ..PLEASE!!

Answers

Answered by devinichenametla

0

Answer:

velocity=6t²-12t

acceleration=(24t-12)1 to 3

24(3-1)-12

36

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