Question

A particular Algebra text has a total of 1382 pages which is broken into two parts. The second part of the book has 64 pages than the first part. How many pages are in each part of the book.

Answer 1

the first part of the book is=1382-64=1318

Answer 2

$<b><i>$Let the number of pages in the first part be x and in the second part be y.

Total pages number of pages is 1382,

Hence, x + y = 1380 …I

The second part of the book has 64 pages more than the first part

y = x + 64 …II

substituting value of y in equation I

x + x + 64 = 1382

2x = 1382 – 64

2x = 1318

x = 659

substituting the value of x in equation (2),

y = 659 + 64

y = 723

$<u>$the pages in the first book are 659 and the pages in the second part are 723.