Question

A particular is moving on a circular path with constant speed v. The change in its velocity after it has turned by an angle 60 is ​

Answer 1

$\huge\underline\blue{\sf Answer:}$

$\red{\boxed{\sf Change\:in\: Velocity (v_2-v_1)=v}}$

$\huge\underline\blue{\sf Solution:}$

$\large\underline\pink{\sf Given: }$

• Velocity is constant i.e , $\sf{v_1=v_2=v}$

• Angle $\theta$=60°

$\large\underline\pink{\sf To\:Find: }$

• Change in Velocity ($\sf{v_2-v_1}$) Or (∆V)= ?

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$\large{♡}$${\boxed{\sf v_2-v_1=\sqrt{{v_1}^{2}+{v_2}^{2}-2v_1v_2cos60°}}}$

On Putting value :

$\large\implies{\sf \sqrt{2{v}^{2}-2{v}^{2}{\frac{1}{2}}}}$

$\large\implies{\sf \sqrt{{v}^{2}}}$

$\huge\red{♡}$$\red{\boxed{\sf Change\:in\: Velocity (v_2-v_1)=v}}$