Question

A particular point on a wire has a constant 250 mA250mA of current flowing through it. How much charge has passed through that point in the wire in 4 seconds?

Answer 1

Answer:

We know

I=q÷t

q=It

given I=250mA =250×10^-3A

$250 \times {10}^{ - 3}$

t=4sec so applying

q=250÷1000×4=(25×4)÷100=25÷25=1C

The charge is 1 coloumb.

Answer 2

The charge has passed through that point in the wire in 4 seconds is 1 C

1. The relation between charge , current and time is given as
2. Q=It here Q is the charge , I is the current flowing in wire and t is the time
3. So here given is I=250 mA =0.250 A
4. 1A=1 Coulomb /Second
5. The charge passing through the wire in 4 seconds is
6. Q = 0.250 C/s x 4 s= 1 C