Question

A particular population of chickens has a frequency for the dominant allele as 0.70 and a frequency for the recessive allele as 0.30. Which expression is the correct way to calculate the frequency of individuals that are heterozygous? A. (0.70) × (0.30) B. (0.70) – (0.30) C. 2 × (0.70) × (0.30) D. 2 × (0.70 – 0.30)

Answer 1

Answer:

C is the correct answer

As the formula

P^2 + q^2 + 2 pq = 0

Answer 2

Answer:

C. 2 x (0.70) x (0.30)

Explanation: