Physics, asked by muky, 11 months ago

A particular straight line passes through origin
a point whose abscissa is double of ordinate o
point. The equation of such straight line is :I want appropriate answer direct solve 1 ​

Answers

Answered by shubham0204
2

Answer:

Explanation:

Let the 2 points through which the line be A( 0 , 0 )-origin and B.

The abscissa ( x-cordinate ) is double of the ordinate ( y-cordinate ). Let k be some real number. Therefore, B = ( 2k , k )

Therefore, using the two-point form of a line,

\frac{ x - x_1 }{ x_1 - x_2 }=\frac{y - y_1}{y_1 -y_2}

Where A = ( 0 , 0 ) = ( x1 , y1 ) and B = ( 2k , k ) = ( x2 , y2 )

We can solve this,

\frac{x}{-2k}=\frac{y}{-k}\\y = \frac{x}{2}\\x=2y

Hope that helps.

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