A particular train takes 18 hours to travel from city A to city B. The train travels at a constant speed throughout the journey and does not stop at any station. One day, it develops an engine problem at city H, which results in the train having to travel at two-third its usual speed for the rest of its journey. As a result, the train reaches the destination 3 hours late. The distance between cities B and H as a percentage of the distance between cities A and B
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Answer:
Let the distance between the two cities A and B be x m.
Time taken by the train to travel from A to B =
10
x
= t
1
(say)
Time taken to come back from B to A =
20
x
= t
2
(say)
Average speed =
Totaltime
Totaldistance
=
t
1
+t
2
x+x
=
10
x
+
20
x
2x
=
3
40
ms
−1
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