Math, asked by as8383940042, 6 months ago

a particular video game has winner for every 3 loser which game has 17 winner for every 51 loser which game has better adds of winning if a third game has 18 loser how many weeks winner are needed to keep the same ratio as the first game?​

Answers

Answered by shaswatbhardwaj866
0

Step-by-step explanation:

introduced an Inequality-adjusted Human Development Index (IHDI). While the simple HDI remains useful, it stated that "the IHDI is the actual level of human development (accounting for inequality)", and "the HDI can be viewed as an index of 'potential' human development (or the maximum IHDI that could be achieved if there were no inequality)". The index does not take into account several factors, such as the net wealth per capita or the relative quality of goods in a country. This situation tends to lower the ranking for some of the most advanced countries, such as the G7 members and others.[4]

The index is based on the human development approach, developed by Mahbub ul Haq, often framed in terms of whether people are able to "be" and "do" desirable things in life. Examples include—Being: well fed, sheltered, healthy; Doing: work, education, voting, participating in community life. The freedom of choice is central—someone choosing to be hungry (as during a religious fast) is quite different from someone who is hungry because they cannot afford to buy food, or because the country is in a famine.[5.... but I am not sure if I canvhgdhd

Answered by bhaskarkampli1971
0

Step-by-step explanation:

The probability of winning in a game if given as the number of winners divided by total number of players in the game.

In the first game;

Number of winners= 1

Number of players= 1+3=4

Probability of winning is;

Prob=\frac{1}{4}= 0.25Prob=

4

1

=0.25

In the second game;

Number of winners= 17

Number of players= 17+51= 68

Probability of winning is;

Prob=\frac{17}{68} =0.25Prob=

68

17

=0.25

The first game and second game have the same odds of winning, i.e. 0.25

In the third game;

Number of winners= x

Number of players= x+18

Probability of winning= 0.25

\begin{gathered}\frac{x}{x+18}=0.25\\ x=0.25*(x+18)\\x=0.25x+4.5\\x-0.25x=4.5\\0.75x=4.5\\x=\frac{4.5}{0.75}\\ x=6\end{gathered}

x+18

x

=0.25

x=0.25∗(x+18)

x=0.25x+4.5

x−0.25x=4.5

0.75x=4.5

x=

0.75

4.5

x=6

The number of winners required is 6

sorry this is worng answer

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