A partire of mass m is released in a smooth hemisphercial bowl from position A find workdone by gravity as it reached the lowest point B.
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Answer:
w = mgR
Explanation:
Work is defined as dot multiplication of force with displacement.
dw = f.dr.CosѲ
Point that to be noted while calculating the work done is that the direction of force applied and displacement is same.
Ѳ is the angle between the displacement and force of their respective direction are different .
And if direction is same then Ѳ = 0
And this formula reduced to
dw = f.dr
In your question....
Displacement(dr) = √(R² + R²)
Displacement = R√2
Ѳ = 45°
Force =. mg
Where m is the mass of the ball....
dw = f.dr CosѲ
put values
w = mg (R√2) Cos45°
w = mgR(√2/√2)
w = mgR
hope you understand
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