A partition wall has two layers A and B, in contact, each made of a different material. They have the same thickness but the thermal conductivity of layer A is twice that of layer B. If the steady state temperature difference across the wall is 60 K, then the corresponding difference across the layer A is (a) 10 K (b) 20 K (c) 30 K (d) 40 K
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Answer:
From fouriers law of conduction
Heat transfer will be same for both walls in contact
so Q
1
=Q
2
so
l
2KAΔT
a
=
l
KAΔT
b
ʕ ꈍᴥꈍʔ
here thickness is same and cross sectional area is also same so will get cancelled
∴2T
a
=T
b
and given that T
b
=50
so T
a
=25K
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