A party of Tourists booked a hotel for Rs 1,200 Three of the members failed to pay as a result each of the others had to pay rupees 20 more how many tourists there in party
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Amount for the booking of hotel = 1200 Rs
Let there be x tourists
When all the tourist paid money, its 1200/x
When 3 members failed to pat, its 1200/(x-3)
So, according to the question:
1200/(x-3) - 1200/x = 20
1200x- 1200x + 3600/ x(x-3) = 20
3600= 20*x(x-3)
3600= 20x^2-60x
-20x^2-60x+3600=0
Now, Factor left side of equation.= −20(x+12)(x−15)=0
Therefore, x=-12 or x= 15
Now , number of tourists = -12 is not possible
Therefore, number of tourists is 15
Therefore, there were 15 tourists in the party
Let there be x tourists
When all the tourist paid money, its 1200/x
When 3 members failed to pat, its 1200/(x-3)
So, according to the question:
1200/(x-3) - 1200/x = 20
1200x- 1200x + 3600/ x(x-3) = 20
3600= 20*x(x-3)
3600= 20x^2-60x
-20x^2-60x+3600=0
Now, Factor left side of equation.= −20(x+12)(x−15)=0
Therefore, x=-12 or x= 15
Now , number of tourists = -12 is not possible
Therefore, number of tourists is 15
Therefore, there were 15 tourists in the party
RUTVI1:
hello what is pat
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