Question

A passanger train starts at 12;00 at a speed of 65kmph, a super fast train starts at 15;00 at a speed of 95kmph can cross the passanger at

Answer 1

Starting at 12.00, let assume that it takes x hour for the passenger train to be crossed (passed) by the super fast train.

The super fast train starts at 15:00, which is 3 hours after the passenger train. This means the super fast train shall have travelled for (x - 3) hours before crossing the passenger train.

The distance travelled by both the trains will be equal at the time of crossing.

Distance = Speed x time

Distance travlled by passenger train = 65x
Distance travelled by the super fast train = 95(x - 3)

These two distances are equal, so,

65x = 95(x - 3)
65x = 95x - 285
65x - 95x = -285
-30x = -285
x = 9.5 hours

This means the super fast train crosses the passenger train 9.5 hours (9 hours 30 minutes) after 12:00

The time will be:

= 12:00 + (9 hours 30 minutes)
= 2130 Hours