Question

A passenger arriving in a new town has to go to the hotel located 10 km away on straight road from station. Due to divergence taxi driver takes him along a circuitous path 23 km long and reaches the hotel in 28 minutes.
(a) What is the average speed of the taxi?
(b) Find the magnitude of the average velocity. Are these two equal?

Answer 1

Answer:

49.3 km/Hr

21.4 km/Hr

Explanation:

Average Speed = Total Distance Covered / Total Time Taken

Distance Covered = 23 km

Time Taken = 28 min = 28/60 hr

Average Speed = 23/(28/60)  =  49.3 km/Hr

magnitude of the average velocity = Displacement / Time Taken

= 10 /(28/60)

= 21.4 km/Hr

No both are not equal