Physics, asked by robelgirma301999, 12 days ago

A passenger at the rear of a train traveling at 15m/s relative to the earth throws a baseball wit a speed of 15m/s in the direction opposite the motion of the train. What is the velocity of the baseball relative to earth as it leaves the thrower's hand

Answers

Answered by saheli123
1

Answer:

The correct option is (a) Zero.

Explanation: We first write our knowns and unknowns with appropriate subscripts Vtc = +15 m/s  [velocity of the train relative to earth] Vbt = -15 m/s [velocity of the baseball relative to the train] We need Vbc the velocity of the baseball relative to earth. Vbc = Vbt + Vtc = + 15 - 15 = 0

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