A passenger bus travel at 7 am with speed 30 km/h and another speedy bus travel at 9 am with speed 45km/h. when the speedy bus will meet the passenger bus?
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Distance between two points A and B is 110 km A motor cycle rider starts from A towards B at 7 am at a speed of 20 km/hr. Another motor cycle rider starts from B towards A at 8 am at a speed of 25 km/hr. Find when will they cross each other.
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The distance from A to B =110km.
The biker from A starts at 7am.
So by 8 am he travels for 1hr.
His speed =20km/hr.
Then the distance covered form 7am to 8am=20km.
Rest of the distance =(110−20)km=90km.
Now the biker from B starts.
Their relative speed =(20+25)km/hr.=45km/hr.
(since they are approaching each other.)
So, the time taken=
relativespeed
distance
=
45
90
hrs.=2hrs.
So they will meet each other after 3 hrs from7am
i.e at 10am.
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