a passenger is travelling in the train moving with a velocity of 40 m/s his suitcase is kept on the berth . the driver of train applies brakes such that the speed of the train decreases at the constant rate to 20 m/s in 5s . what should be the minimum coefficient of friction b/w the suitcase and the berth if the suitcase is not to slide during retardation of the train ?
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Answer:
0.408
Explanation:
coefficient of friction = F/R
whereby;
F = ma
F =m(V-U/t)
F = m (20-40/5)
F=4m
therefore; c.of friction = F/R
=ma/mg
=4m/9.8m
m and m cancel out;
=0.408 Ans
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