A passenger jeep is traveling at 40 m / s when the breaks are applied. It comes to a stop after 10 seconds
Find
a) acceleration
b) distance travel after the breaks are applied.
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Answer:
Intial velocity(u)=40 m/s
final velocity (v)=0 m/s
time (t)=10s
From 1st equation of motion
v=u+at
0=40+10a
a=-40/10
a= -4
From 3rd eq of motion
v^2= u^2+2as
s=5m
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