Question

A passenger sitting in the train with a constant horizontal velocity drops a ball vertically

downwards. What is the path observed by-


i. a man in the train.


ii. a man standing on the ground near the train


iii. a man in second train moving in the opposite direction to the first train on parallel

track.​

Answer 1

Explanation:

As at the moment when the stone was dropped the train was stationary so the initial vertical velocity of the stone will be zero even with respect to the observer.

Now with respect to the passenger, the stone will have two acceleration one downward due to gravity and another in opposite motion of train because the passenger is on an accelerated frame of reference.

Now downward displacement is y=

2

gt

2

and horizontal displacement as x=−

2

at

2

where a is acceleration of train.

We see that both x and y are dependent on same power of time t i.e.,t

2

so path will be a straight line. just put t

2

=

a

2x

in exprexxion of y we get path equation as y=

a

gx

which is a stright line in xy plain.

PLEASE MARK AS BRAINIEST.

Answer 2

Answer:

Both trains travel the same distance in time to units

SOLUTION

Slope of the velocity time graph at ant time , gives acceleration at that point of time. The figure shows that the train has a varying acceleration while a has a constant acceleration.

Area under velocity time graph given displacement in the interval Here, has covered a large displacement than . This can be attribute to it goining speed quickly. But the velocity at to both are came.

Explanation:

I hope it is helpful for you