Question

a passenger takes 2 hours less for a journey of 300 km if its speed is increased by 5 kilometre per hour from his usual speed what is his usual speed

Answer 1

ANSWER:

Take usual speed = x km/hr

distance= 300km

time taken= 300/x hr

New speed= x+5 km/hr

time taken= 300/x+5 hr

300/x - 300/x+5 = 2

Simplify and form a quadratic equation. Then solve it. You will get two values of x. Take the positive value. If both the values are positive then you can take anyone of them as the answer.

HOPE THIS HELPS!

Answer 2

Answer:

Let the usual speed of the train be y km / hr .

A.T.Q.

$\displaystyle{\frac{300}{y} -\frac{300}{y+5} =2 }$

300 ( y + 5 ) - 300 y = 2 y ( y + 5 )

y² + 5 y - 750 = 0

y² + 30 y - 25 y - 750 = 0

( y + 30 ( y -25 ) = 0

y = - 30 or y = 25

Since , speed of train can't be negative .

Therefore , the usual speed of the train is 25 km / hr .