Math, asked by arishnaashi, 1 month ago

. A passenger train having speed of 80 km/h
runs from a station 6 hours after a goods
train has started from that station and
crossed the goods train after 4 hours. What
is the speed of goods train?
(A) 32 km/h (B) 48 km/h
(C) 60 km/h (D) 50 km/h​

Answers

Answered by IlMYSTERIOUSIl
34

Answer -

  • Speed of passenger train - 80 km/h
  • Time taken - 4 hour

Distance goods train travel in 10 hr =

 \rm  :\longrightarrow distance \:  = speed \times time

 \rm  :\longrightarrow distance \:  = 80 \times 4

\rm  :\Longrightarrow distance \:  =  \bold{320}

Now ,

Speed of goods train =

 \rm  :\longrightarrow speed \:  =   \dfrac{distance}{time}

 \rm  :\longrightarrow speed \:  =   \dfrac{320}{10}

 \rm  :\Longrightarrow speed \:  =   \bold{32 km/hr}

\begin{gathered} \underline{ \qquad\qquad\qquad\qquad\qquad\qquad\qquad\qquad} \\ \end{gathered}

Hence , Option A is correct

Answered by sanjeetsrijan
0

Step-by-step explanation:

Speed of passenger train - 80 km/h

Time taken - 4 hour

Distance goods train travel in 10 hr =

\rm :\longrightarrow distance \: = speed \times time:⟶distance=speed×time

\rm :\longrightarrow distance \: = 80 \times 4:⟶distance=80×4

\rm :\Longrightarrow distance \: = \bold{320}:⟹distance=320

Now ,

Speed of goods train =

\rm :\longrightarrow speed \: = \dfrac{distance}{time}:⟶speed=

time

distance

\rm :\longrightarrow speed \: = \dfrac{320}{10}:⟶speed=

10

320

\rm :\Longrightarrow speed \: = \bold{32 km/hr}:⟹speed=32km/hr

\begin{gathered}\begin{gathered} \underline{ \qquad\qquad\qquad\qquad\qquad\qquad\qquad\qquad} \\ \end{gathered}\end{gathered}

Hence , Option A is correct

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