Question

a passenger train of length 60m travels at a speed of 80km/h . Another freight train of length 120m travels at a speed of 30 km/h .The ratio of times taken by the passenger train to completely cross the freight train when they are moving in the small direction,and in the opposite direction is​

Answer 1

Answer:

t1=v−ux=50x

t2=v+ux=100x

t2t1=511

Assuming the locomotive is approximately of the same size, effectively the train is now 25 coaches long, with each coach approximately 68 ft. long. So that makes the avg length approximately (25 * 68 * 0.3048) = 518.16 m.This means that from the point when the engine or the front of the train crosses the pole to the point when the back of the train reaches the pole, we have 9 seconds. Thus we can get the length of the train by calculating the distance that the train travels in 9 seconds. We have the speed of the train = 60 km/hr.is complicated, but thumb rules can work if the structure is simple. It is always recommended to use structural design software like ETabs or Staad pro for design. In a beam of up to 5 meters length, secondary spans of up to 4 meters, wall loads of up to 8 kN per running meter, I can use steel as below.