Question

A PASSENGER TRAIN, RUNNING AT A SPEED OF 80KM/HR LEAVES A RAILWAY STATION 6 HOURS AFTER A GOODS TRAIN LEAVES AND OVERTAKES IT IN 4 HOURS. WHAT IS THE SPEED OF THE GOODS TRAIN??

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Answer 1

Answer:

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Answer 2

Answer:

Let the speed of the good train be x km/hr.

Now when the good train is overtaken, it has travelled for a total time of 10 hours,as it started 6 hours early and took 4 hours to be overtaken. So, the distance travelled by is:

 distance=speed×time=10x kmdistance=speed×time=10x km

Also, by the time the train is overtaken, the passenger train should have travelled the same distance as the goods train. It is given that the speed of the passenger train is 80 km/hr and time taken is 4 hours.

 distance=speed×time=80×4=320 kmdistance=speed×time=80×4=320 km

Now, we will equate the two distances that we found in the above case, we get

 10x=32010x=320

 x=32 km/hrx=32 km/hr

Therefore, the speed of the good train is 32 km/hr. 

This is the answer.

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