Question

A passenger train running from Sitapur to Gitapur meets with an accident 50 kms from Sitapur, after which it travels at 3/5 times its original speed and arrives 3 hours late at Gitapur. If the accident had occurred 50 kms farther, it would have been only 2 hours late.find the distance between Sitapur and gitapur?and what is the original speed of train?​

Answer 1

Answer:

here is less mathematical approach.

let the two end points between which this train is running be A and B. Also suppose that accident occurs at C which is at a distance of 50km from A. thus we have

A---------50km----------C----------------------------B 1)

Time taken to travel the distance after the accident i.e. CB is 35 minutes more than the usual time.

now, if the accident were to occur at 24 km farther, then train would have reached only 25 minutes late. i.e.

A--------50 km----------C---------24--------D---------------B 2)

if we look at the situation depicted in 1) and 2) we will see that 10 minute difference in time is occurring because of this 24 Km. which is traveled by its usual speed (=x) in the later case. thus we have:

24×4/3x -24/x =10/60

32/x-24/x = 1/6

solving this we get x= 48km/h

Step-by-step explanation:

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