Question

a passenger train takes 1hour less for journey for 150km if it speed is increased by 5km/h from it usual speed. find the usual speed of train.
plz. give full solutions...
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Answer 1

Answer:

25

Step-by-step explanation:

Let the usual speed of the train be xkm/hr

⇒  Distance covered in the journey=150km

⇒  Time taken by the train with usual speed =  

x

150

​  

hr

⇒ New speed of train =(x+5)km/hr

⇒  Time taken by the train after increasing the speed =  

x+5

150

​  

hr

x

150

​  

−  

x+1

150

​  

=1

⇒  150(  

x

1

​  

−  

x+5

1

​  

)=1

⇒  150(  

x(x+5)

x+5−x

​  

)=1

⇒  150(5)=x(x+5)

⇒  750=x  

2

+5x

⇒  x  

2

+5x−750=0

⇒  x  

2

+30x−25x−750=0

⇒  x(x+30)−25(x+30)=0

⇒  (x+30)(x−25)=0

⇒  x+30=0 and x−25=0

⇒  x=−30 and x=25

Speed cannot be negative.

∴  The usual speed of the train is 25km/hr

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Answer 2

Step-by-step explanation:

speed is equals to X

speed is equals to X + 5

speed is equals to distance by time

x+5=150/1

x+ 5 =150

x= 125 kmph

the usual speed is equals to 125 kilometre per hour

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