A passenger train takes 2 hours less for a journey of 300 km if
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Step-by-step explanation:
Let the usual speed of the train be y km / hr .
A.T.Q.
300 ( y + 5 ) - 300 y = 2 y ( y + 5 )
y² + 5 y - 750 = 0
y² + 30 y - 25 y - 750 = 0
( y + 30 ( y -25 ) = 0
y = - 30 or y = 25
Since , speed of train can't be negative .
Therefore , the usual speed of the train is 25 km / hr...
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