Question

A passenger train takes 2hrs less for a journey of 300km of its speed by 5km/hr from its ususal speed​

Answer 1

Let x = normal speed  

Let x = normal speed  300 / (x + 5) + 2 = 300 / x  

Let x = normal speed  300 / (x + 5) + 2 = 300 / x  . . . combine left side into a single fraction  

Let x = normal speed  300 / (x + 5) + 2 = 300 / x  . . . combine left side into a single fraction  (310 + 2x) / (x + 5) = 300 / x  

Let x = normal speed  300 / (x + 5) + 2 = 300 / x  . . . combine left side into a single fraction  (310 + 2x) / (x + 5) = 300 / x  . . . cross multiply  

Let x = normal speed  300 / (x + 5) + 2 = 300 / x  . . . combine left side into a single fraction  (310 + 2x) / (x + 5) = 300 / x  . . . cross multiply  310x + 2x^2 = 300x + 1500  

Let x = normal speed  300 / (x + 5) + 2 = 300 / x  . . . combine left side into a single fraction  (310 + 2x) / (x + 5) = 300 / x  . . . cross multiply  310x + 2x^2 = 300x + 1500  2x^2 + 10x - 1500 = 0  

Let x = normal speed  300 / (x + 5) + 2 = 300 / x  . . . combine left side into a single fraction  (310 + 2x) / (x + 5) = 300 / x  . . . cross multiply  310x + 2x^2 = 300x + 1500  2x^2 + 10x - 1500 = 0  x^2 + 5x - 750 = 0  

Let x = normal speed  300 / (x + 5) + 2 = 300 / x  . . . combine left side into a single fraction  (310 + 2x) / (x + 5) = 300 / x  . . . cross multiply  310x + 2x^2 = 300x + 1500  2x^2 + 10x - 1500 = 0  x^2 + 5x - 750 = 0  (x - 25) (x + 30) = 0  

Let x = normal speed  300 / (x + 5) + 2 = 300 / x  . . . combine left side into a single fraction  (310 + 2x) / (x + 5) = 300 / x  . . . cross multiply  310x + 2x^2 = 300x + 1500  2x^2 + 10x - 1500 = 0  x^2 + 5x - 750 = 0  (x - 25) (x + 30) = 0  x = -30 <== invalid negative time  

Let x = normal speed  300 / (x + 5) + 2 = 300 / x  . . . combine left side into a single fraction  (310 + 2x) / (x + 5) = 300 / x  . . . cross multiply  310x + 2x^2 = 300x + 1500  2x^2 + 10x - 1500 = 0  x^2 + 5x - 750 = 0  (x - 25) (x + 30) = 0  x = -30 <== invalid negative time  x = 25 km / h <===== answer

Let x = normal speed  300 / (x + 5) + 2 = 300 / x  . . . combine left side into a single fraction  (310 + 2x) / (x + 5) = 300 / x  . . . cross multiply  310x + 2x^2 = 300x + 1500  2x^2 + 10x - 1500 = 0  x^2 + 5x - 750 = 0  (x - 25) (x + 30) = 0  x = -30 <== invalid negative time  x = 25 km / h <===== answerStep-by-step explanation:

Answer 2

Hii

Refer to the attachment ✌️