Question

A password consists of five digits, in this format "ABCDE".
Given: D = 3B.. and A + B + C + D + E = A*D
Also you have three sets:
1 2 7 4 5 where only one correct number but wrong position
2 6 8 5 7 with two correct numbers, one of them is in the right position 6 1 7 4 2 with two correct numbers and positions..
What is the password?

Answer 1

Given : A password consists of five digits, in this format "ABCDE".

Given: D = 3B.. and A + B + C + D + E = A*D and few rules

To find :  What is the password?

Solution:

1 2 7 4 5 where only one correct number but wrong position

=> Hence 4 numbers should come from 0 , 3 , 6 , 8 , 9

6 1 7 4 2 with two correct numbers and positions..

6 is  correct  and correct position

and  ( 1 2 7 4  can have one correct)  so  5 is not correct

7  , 4 can not be correct as their position is same in 1 2 7 4 5   & 6 1 7 4 2

While one has correct position , but one does not

Either 1 is correct or 2 is correct

2 6 8 5 7 with two correct numbers    one of them is in the right position

one number correct  is 6   and wrong position

5   & 7 are not  correct  

so we left with 2 & 8

2 can not be correct as its should be in correct position  in 2 6 8 5 7   & 6 1 7 4 2   but position are different

Hence  8 is correct

now 2 is not correct hence 1 must be correct

2 6 8 5 7      - position of 8 is correct

6 1 7 4 2      -  position of 6 & 1 is correct

we got

6  1  8  D  E

D = 3B => D = 3

Hence

 6  1  8  3  E

A + B + C + D + E = A*D

6 + 1 + 8 + 3 + E = 6 * 3

=> 18 + E = 18

=> E = 0

61830  is password

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