Question

A path 2.5 m wide runs along inside the boundary of a park whose length and breadth are 72 m and 43 m respectively. Find the area of Park and cost of levelling at rs 1.25 per m square.

Answer 1

area of rectangle=l×b
72×43
3096m

3096×1.25
3870 rupees

Answer 2

Step-by-step explanation:

Answer:

→ Area of the path = 861 m² .

Step-by-step explanation:

Given :-

→ Width of path = 3.5 m .

→ Side of square park along with path = 65 m .

To find :-

→ Area of the path .

Solution :-

∵ Side of square park without the path = 65 - ( 2 × 3.5 )  =  58 m .

Now, area of square park alnog with path

= side × side .

= ( 65 × 65 ) m² .

= 4225 m² .

And, area of square park without path

= side × side .

= ( 58 × 58 ) m² .

= 3364 m² .

Therefore, area of the path = ( 4225 - 3364 ) m² .

= 861 m² .

And, cost of measuring the rest of the field = 3364 × 25 .

= ₹86100 .

Hence, it is solved .

THANKS