A path 2.5 metre wide runs all the way round a plot of land measuring 40m long by 24m wide. What is the area of the path?
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Let's draw the figure (I used ms paint for the figure). From the figure:
- DA=CB=24m
- AB=CD=40m
- Path- 4.5 m wide.
We need to find the brown coloured area.
Now, Area of the plot (bigger rectangle) - l×b
⇒(40×24)m²
⇒960m²
Now, we know that the path is 2.5 m wide.
So OP=2.5m, QT=2.5m.
Together, OP+QT+PQ=AD.
We know that AD=24m, OP=2.5m, QT=2.5m.
∴2.5+2.5+PQ=24.
PQ=24-5
PQ=19 m.
Similarly, US=2.5 m, VP=2.5 m.
Together, US+VP+PS=CD.
We know that CD=40 m, US=2.5 m, VP=2.5 m.
∴2.5+2.5+PS=40
PS=35 m.
Now, area of the smaller rectangle PQRS is l×b. PS is length, PQ is breadth in PQRS.
Area = PS×PQ
=35×19
=665 m².
Area of path - Area of bigger rectangle (ABCD) - Area of smaller rectangle (PQRS)
Area = 960 - 665
= 295m²
HOPE THIS HELPS :D
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