A path 2 m wide is built along the border and inside a square garden of side 32m. Find the area of the path.
Answers
Answer:
Area of the square garden=s×s
side =30m
area =30m ×30m
=900m^2
area of the inner square garden=
one side=30m-4m(after building the path)
side =26m
area=26m×26m
=676m^2
area of the path=
(area of outer square garden)-(area of inner square garden)
=900-676
=224m^2
therefore, area of path =224m^2
Step-by-step explanation:
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To Find :
The Area of the Path.
Given :
- Length of the Square garden = 32 m
- Width of the Path = 2 m
We Know :
Area of a Square :
Concept :
Since the path was build along the length of the square garden it formed a new Square .
Length of New Square = length of the original square - 4
==> (32 - 4) m
==> 28 m
Hence the length of the new Square is 28 m
Now , according to the information :
Area of Path = Area of Square garden - Area of Square garden with the path
By solving it we will get the area of the path.
Solution :
Area of the Square garden :
- Side of the Square garden = 32 m
Using the formula for Area of a Square and by Substituting the value in it , we get :
Hence ,the area of the Square garden is 1024 m².
Area of the New Square garden :
- Side of the new Square = 28 m
Using the formula for Area of a Square and by Substituting the value in it , we get :
Hence, the area of the Square garden is 784 m².
Area of the Path :
Area of Path = Area of Square garden - Area of Square garden with the path
By substituting the values in it , we get :
»» Area of Path = (1024 - 784) m²
»» Area of Path = 240 m²
Hence , the Area of the path is 240 m².