A path 2 m wide runs inside a square feild of side 72 m . find the area of the path.
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ɴᴀᴛᴜʀᴇ ɴᴇᴠᴇʀ ɢᴏᴇs ᴏᴜᴛ ᴏғ sᴛʏʟᴇ
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Step-by-step explanation:
Given: width of a path= 2m
Side = 72m
Area of square ABCD =s*s
= (72-(2+2))m
= 5184m^2
Dimension of square EFGH =s*s
= (68*68)m^2
= 4624m^2
Area of path = (5184 - 4624)m^2
= 560m^2
therefore, Area of path = 560m^2
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