Question

A path 2 m wide runs inside a square
feild of side 72 m , find the area of the
path.​

Answer 1

Answer:

Hello!!

Step-by-step explanation:

Let ABCD a square field of side 72m and the shaded region be the path.

Then:

AD = 72m , XP = 2m , SY = 2m , XY = AD

you have that:

XP + PS + SY = AD;

from which:

PS = AD - XP - SY = 72 - 2 - 2 = 68m

We have:

PQRS in a square of side 68m

The area of path = Area of ABCD - Area of PQRS ;

=(72m)² - ( 68m)²,

=5184 m² - 4624 m² ;

=560m²

Hope that helps you..

Buhbye! ♡

Answer 2

Answer:

Agree to this answer.

Step-by-step explanation:

Uppar ka.