A path 2 metre run inside a square field of side 72m find the area of the path.
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Answer:
let ABCD a square fieldof side 72m and the shaded region be the path.
Then :
AD = 72m , XP=2m, SY = 2m ,XY = AD
you have that:
XP + PS + SY = AD ;
from which:
PS = AD - XP - SY = 72-2-2 = 68m
We have:
PQRS in a square of side 68m
The area of path = Area of ABCD - Area of PQRS;
=(72m)²-(68m)²;
=5184 m² - 4624 m²;
=560 m²
Step-by-step explanation: PLEASE MAKE ME THE BRAINLEIST
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