Math, asked by mahreenshafiq90, 2 months ago

A path 2m wide runs around the inside of a square park of side 40m. Find the area of the path.​

Answers

Answered by oindriladatta
1

Answer:

236 m²

Step-by-step explanation:

the area of the park 40×40= 1600 m²

area including path= (40+2+2)² = 44×44 = 1836 m²

1836-1600 = 236

Answered by BloomingBud
4

Given:

  • The side of the square park is 40 m.
  • A 2m wide path runs around inside the square park.

To find:

  • The area of the path.

Look at the attached image, (drawn according to the figure)

We get two squares ABCD, and square PQRS

  • The side of the square PQRS,

= 40 - 2 - 2

= 36m

Now,

Area of the square ABCD = (side)² units sq.

Area of the square ABCD = (40)²

Area of the square ABCD = 1600 m sq.

And,

Area of the square PQRS = (side)² units sq.

Area of the square PQRS = (36)²

Area of the square PQRS = 1296 m sq.

Thus,

  • Area of the path = Area of square ABCD - Area of square PQRS

Area of the path = 1600 - 1296

Area of the path = 304 m sq.

Hence,

  • The area of the path (2m) wide running around inside the square field is 304 m sq.
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