A path 2m wide runs around the inside of a square park of side 40m. Find the area of the path.
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1
Answer:
236 m²
Step-by-step explanation:
the area of the park 40×40= 1600 m²
area including path= (40+2+2)² = 44×44 = 1836 m²
1836-1600 = 236
Answered by
4
Given:
- The side of the square park is 40 m.
- A 2m wide path runs around inside the square park.
To find:
- The area of the path.
Look at the attached image, (drawn according to the figure)
We get two squares ABCD, and square PQRS
- The side of the square PQRS,
= 40 - 2 - 2
= 36m
Now,
Area of the square ABCD = (side)² units sq.
Area of the square ABCD = (40)²
Area of the square ABCD = 1600 m sq.
And,
Area of the square PQRS = (side)² units sq.
Area of the square PQRS = (36)²
Area of the square PQRS = 1296 m sq.
Thus,
- Area of the path = Area of square ABCD - Area of square PQRS
Area of the path = 1600 - 1296
Area of the path = 304 m sq.
Hence,
- The area of the path (2m) wide running around inside the square field is 304 m sq.
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