Question

A path 2m wide runs inside a square field of side 72 m find area of path

Answer 1

It is given that the length of the side of square is 72 m and a path runs inside the square field with the width of 2 m.


From the properties of square,

Area of square : side^2


Therefore,
= > Area of the square field = ( 72 m )^2

= > Area of the square field = 5184 m^2


Now,
A path of width 2 m is there, and forming a new square of length of ( 72 - 2 - 2 ) m i.e. 68 m^2


Therefore,
= > Area covered under the path = ( 68 m )^2

= > Area covered under the path = 4624 m^2



Hence,
Area of the path = 5184 m^2 - 4624 m^2

Area of the path = 560 m^2


Thus,
Area covered by the path is 560 m^2.
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Answer 2

Answer:

The area of path is 560 m².

Step-by-step explanation:

The given field is a square with side 72 m.

So, Area of field = (side)² = (72)² = 5184 m²

Now, it is given that the path runs 2 m wide inside the square.

So, the side of the square formed inside the field = 72 - (2 + 2) = 68 m

Now the area of inner square =  (side)² = (68)² = 4624 m²

So, the area of path = Area of square field - area of inner square

                                 = 5184 - 4624 = 560 m²